|Nộp bài||Các bài nộp||Làm tốt nhất||Về danh sách bài|
KL11B - Arnook Defensive Line
Based on the latest intelligence reports, Chief Arnook of the northern tribe has become suspicious of the warrior nations that dwell south of the border. The chief has ordered his warriors to protect the southern border which runs parallel to the 54o latitude line and stretches between the longitudes of 1o to 1000,000,000o, inclusive.
Each warrior is assigned the task of protecting a segment of the border defined to lie between longitudes “a” and “b”, inclusive. No two warriors are assigned to protect the exact same segment. Bound by loyalty to his chief, a warrior will inform the chief upon his arrival at his appointed post and will never leave once he arrives.
Your task is to write a program that performs the following two operations to help Chief Arnook track the status of his border protection.
+ a b
a warrior assumes his position and protects the segment between longitudes “a” and “b”, inclusive.
? c d
computes the number of warriors who completely protect the segment between longitudes “c” and “d”, inclusive. The segment between the longitudes “c” and “d”, inclusive, is said to be completely protected by a warrior X if and only if warrior X protects a segment between
“a” and “b”, inclusive, and a ≤ c ≤ d ≤ b.
The input starts with an integer N (1 ≤ N ≤ 500000), on a line by itself, that indicates the number of operations. Each of the following N lines contains one operation. The description of an operation consists of a character “+” or “?” followed by two integers on a line by itself. The entries on a line are separated by single blank spaces.
There is one output line for each input line that starts with the operation “?”. The output consists of a single integer that represents the number of warriors who completely protect the corresponding segment at the time.
There is no output for input lines that start with the character “+”.
Input: 9 + 5 10 + 7 20 + 3 15 ? 9 12 + 10 20 ? 8 9 + 6 30 ? 8 9 ? 9 12 Output: 2 3 4 3
|Được gửi lên bởi:||Race with time|
|Thời gian chạy:||3.636s|
|Giới hạn mã nguồn:||50000B|
|Cluster:||Cube (Intel G860)|
|Ngôn ngữ cho phép:||Tất cả ngoại trừ: ASM64 GOSU PERL6 PYPY RUST SED|
|Nguồn bài:||ACM ICPC Kuala Lumpur 2011|
2012-07-12 02:55:17 Hy Trường Sơn
accepted trên uva mà lên VOJ vẫn chạy quá lâu
2012-03-31 03:33:22 kệ anh chứ
Last edit: 2012-03-31 13:58:58